Theorem: All numbers are equal.I went over it twice, and I couldn't find the error.

Proof: Choose arbitrary a and b, and let t = a + b. Then

a + b = t`0: a + b = t`

1: (a + b)(a - b) = t(a - b)

2: a^2 - b^2 = ta - tb

3: a^2 - ta = b^2 - tb

4: a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4

5: (a - t/2)^2 = (b - t/2)^2

6: a - t/2 = b - t/2

7: a = b

So all numbers are the same, and math is pointless.

Let's go through it again, with actual numbers.

Let a=3, b=5. Then, t=8

`0: 3 + 5 = 8`

» 8 = 8

Multiply both sides by (3 - 5) [-2]

1: (3 + 5)(3 - 5) = t(3 - 5)

» -16 = -16

FOIL (no value change)

2: 3^2 - 5^2 = 8(3) - 8(5)

» 9 - 25 = 24 - 40

» -16 = -16

Add 5^2 and subtract 8(3) from both sides [+25-24=+1]

3: 3^2 - 8(3) = 5^2 - 8(5)

» 9 - 24 = 25 - 40

» -15 = -15

Add (8^2)/4 to both sides [+16]

4: 3^2 - 8(3) + (8^2)/4 = 5^2 - 8(5) + (8^2)/4

» 9 - 24 + 64/4 = 25 - 40 + 64/4

» 1 = 1

Factor (no value change)

5: (3 - 8/2)^2 = (5 - 8/2)^2

» (-1)^2 = (1)^2

**Ahhh...**

Root both sides

6: 3 - 8/2 = 5 - 8/2

» 3 - 4 = 5 - 4

» -1 = 1

**Umm...**

Add 8/2 from both sides [+4]

7: 3 = 5

**Eep.**

So wonder_yak is correct, the problem is with rooting both sides. Step 6 should be:

`6: ±(3 - 8/2) = ±(5 - 8/2)`

Isn't math

*fun*?

Well, I'm not quite sure how to articulate this, but aren't you essentially disregarding sign...specifically when you square and then square-root the equation?

ReplyDeleteI'm pretty sure that is why this is false, I just wish I knew the algebraic rule that was being broken.

_kris

Or, more specifically: in lines 5 - 7 when you factor and then square-root...

ReplyDelete"Isn't math fun?"

ReplyDeleteUm. See my post on Friday, most notably, the third section.

My answer is: NO! :)

if i tried to read and understand that post.... i would get a headache

ReplyDeleteNot too hard, space cadets. If A not equal to B then at step 5 one expression has to be negative and the square root of a negative is not allowed.

ReplyDeleteWow, blogboy. Did you even

ReplyDeletelookat step 5? Both sides are squared. The square of any number (negative or positive) is positive. No one is rooting negative numbers. The problem isn't rooting a negative, it's assuming that a root results in a positive.You fail it.

Ok, ok, enough maths Phoenix! More stories about falling off your bike please...

ReplyDeleteYeah, yeah, yeah... :-) I really need to update this. I never did finish the Tokyo story, and there have been a LOT of new news since then. The Asahi festival, fireworks in Takefu, Summer English seminars, this weekend's Otaiko festival (assuming I can find a ride), all the stupid movies I've seen recently... so much to post about.

ReplyDelete